*This is one of my old college lab reports!
Forest Thomer
Introduction
Mendel proposed the Law of Independent Assortment. This law is in relation to the known fact that mutant genes are produced in frequencies that result from random movement in meiotic chromosome pairs. According to this law the alleles of different genes assort independently. Yet this law only applies when the loci are on different pairs of chromosomes. A linkage gene would describe mutants located on the same homolog (chromosome pair) (Thompson 2006).
Thus the purpose of this experiment was to tangibly determine if the recessive mutant genes for apterous wings and Sepia eye color (black) are linked in the diptera species Drosophila melanogaster or commonly referred to as the fruit fly. Since the experiment aims to prove that the genes are linked the null hypothesis would imply there to be no significant difference between what is observed and what is expected, if and only if the genes are linked. If the genes are linked we can expect a 2, 1, 1, 0 ratio. This meaning 2/4 of the cultivated flies will not exhibit either recessive trait, ¼ will exhibit apterous wings and red eyes, ¼ will have normal wild type wings and sepia eyes, and none will have the presence of both recessive traits due to them being physically located on the same chromosome. If the genes are not linked we can expect a 9,3,3,1 ratio in which 9/16 of the cultivated flies will not exhibit either recessive trait, 3/16 will exhibit apterous wings and red eyes, 3/16 will have normal wild type wings and sepia eyes, and 1/16 will have the presence of both recessive traits due to crossing over, thus demonstrating them being located on different chromosomes.
Materials
For the experiment to be fulfilled three vials of various genotypic and phenotypic Drosophila melanogaster were provided by the instructor. One vial included nothing but Wild Type flies. Thus their eye color was expressed as red and they had the presence of wings. The second vile had sexually diverse members, whom were homozygous recessive for the presence of no wings (apterous) while having red wild type eyes. The third vile included sexually diverse members of the species whom were homozygous recessive for the presence of sepia (dark/black) eye color and exhibited the wild type (long) wing characteristic. The flies were to be considered as such since the “provider” was a specialized carrier of the specimens.
Separate autoclaved vials were prepared using a commercially prepared, instant type of medium. The medium was prepared by placing a “standard measure” of dry medium and about 15mL of water into autoclaved vials. The mixture was swirled to remove air bubbles and then allowed to dry for two minutes. A sterilized sponge stopper was used to prevent further contamination and as a barrier to prevent the specimens from escaping once introduction had occurred. CO2 gas was used to facilitate cultivation as were horse haired brushes. A microscope was provided in order to aid sexual identification and also make recessive trait “expression” more accurate. (I will not provide a diary of activities concerning fruit fly culturing because such a description is not necessary for this lab report).
Once desired virgin female flies were cultivated a parental cross involving thirteen (13) male flies and thirteen (13) female flies was made on 10/29/06. The parental cross involved thirteen males that exhibited sepia eye color and the wild type (present) wing. This cross also involved thirteen virgin female flies which exhibited wild type eye color, red eyes, and apterous (the lack of wings) wing type. It is crucial to cultivate virgin females in order to guarantee the results are accurate. This is the case because females store sperm from previous partners. In order to “ensure” virgin female flies are cultivated, cultivation must be done within 2-4 hours after the fly ecloses/emerges from their pupae. Other precautions include clearing adults from the vial once a “significant” and/or reasonable number of pupae appear (roughly 5-6 days after parental cross has been made). On 11/6/06 and 11/9/06 the F1 generation was counted. The F2 generation was introduced into a sterile vial on 11/6/06. The F2 generation was then counted on 11/13/06 and 11/20/06. The F2 generation was produced by taking ten (10) males that exhibited sepia eye color and the wild type (present) wing and ten (10) female flies which exhibited wild type eye color, red eyes, and apterous (the lack of wings) wing type. All fly crosses were done in a vial which was placed inside an incubator set at 27 degrees Celsius. A Drosophila melanogaster life cycle diagram is located at figure 1.
FIGURE 1
http://media.nasaexplores.com/lessons/04-006/images/life-cycle.gif
Results
The following diagrams document the observed flies from both the F1 and F2 generation cultivated on the mentioned dates.
F1 Generation
Phenotypes Male Female Total
11/6/06.………11/9/06 11/6/06.……11/9/06
Long wings, red eye color 9 28 6 42 85
Apterous wings, red eye color 0 0 0 0 0
Long wings, sepia eye color 0 0 0 0 0
Apterous wings, sepia eye color 0 0 0 0 0
Totals 37 48 85
F2 Generation
Phenotypes Male Female Total
11/13/06.……11/20/06 11/13/06.……11/20/06
Long wings, red eye color 2 63 34 96 195
Apterous wings, red eye color 2 14 0 0 0
Long wings, sepia eye color 0 0 0 0 0
Apterous wings, sepia eye color 0 0 34 96 0
Totals 81 130 211
A Chi-Square Test was preformed using the F2 Generation data. A Chi-Square Test is a commonly used basic statistical tool used to compare observed experimental results with the values that are theoretically to be expected (Thompson 2006). This test involved the use of a Chi-Square diagram handed out in class in order to determine the p-value. A p-value is the probability of rejecting the null hypothesis (that there is no difference between observed and expected), when the null hypothesis is true. In other words the p-value gives an approximate value for the error of falsely stating that there is a significant difference between your observed numbers and the expected numbers (Carter 2002). This test was conducted to determine the statistical probability/likely-hood of two different null hypotheses. The null hypothesis used that tested genes as linked was as follows…
-There is no significant difference between what we observed and what is expected if the genes are linked.
The null hypothesis that tested genes as not linked was as follows…
-There is no significant difference between what we observed and what is expected if the genes are not linked.
This statistical test requires taking the sum of (observed-expected) ^2/expected (formula used for conducting this statistical test) for each expected class. Observed is the total number of flies observed for a class, for example 195 flies with wild type (long) wings and red eyes were observed in that class. We then take the number of observed flies and subtract the number of expected flies. The number of flies expected varies depending on which null hypothesis we are testing. As mentioned before, if the genes under examination are linked then we can expect a 2, 1, 1, 0 ratio. This meaning 2/4 of the cultivated flies will not exhibit either recessive trait, ¼ will exhibit apterous wings and red eyes, ¼ will have normal wild type wings and sepia eyes, and none will have the presence of both recessive traits due to them being located on the same chromosome. If the genes are not linked we can expect a 9,3,3,1 ratio in which 9/16 of the cultivated flies will not exhibit either recessive trait, 3/16 will exhibit apterous wings and red eyes, 3/16 will have normal wild type wings and sepia eyes, and 1/16 will have the presence of both traits due to them being located on different chromosomes.
We take the mentioned rations and multiply them with the total number of flies observed. For example…
If the genes are linked and we are trying to determine the expected (e) we would take 2/4 for the first class (not exhibiting either recessive trait) and multiply it with 211 (the total number of flies cultivated). The 2/4 ratio is used simply due to the “assumption” the genes are linked. Other statistical tests which have been explained in class have proven such a pattern, hence the reason the ratios used are being used. The resulting number is a statistical expectation in reference to the number of flies to be cultivated that fit the class description.
The (e) value for each class will be determined in that fashion. Upon finding the difference between observed and expected, we than square the resulting number and divide it by the class expected (e) value.
Once this has been determined and the sums of each equation have been added up for all the involved classes, an X^2 (Chi-Square) value has been found. Using a Chi-Square sheet handed out in class, the probability of this particular X^2 value was to be determined. In order to accomplish this, the degrees of freedom had to be determined simply to use the chart. This value is found by subtracting one from the number of expected classes. Thus 2 was the degrees of freedom used to test the null hypothesis dealing with the genes being linked (three expected classes minus one) and 3 was the degrees of freedom used to test the null hypothesis dealing with the genes not being linked (four expected classes minus one).
Discussion
The tested null hypotheses were rejected. As explained in class the genes are not linked. The mutant gene for sepia eye color appears on chromosome number (III) 3 and the mutant gene for apterous wings appear on chromosome number (I) 1 (Raymond 1988). Thus from a “tangible/visual” perspective the genes are not linked/found on the same chromosome. This means that crossing over should have occurred. The expected phenotypic ration of 9/16, 3/16, 3/16, and 1/16 should have been observed. Yet the genetic recombination observed in the F2 generation never produced any organisms with the wild type long wing and the mutant recessive gene for sepia eye color. According to the statistical results both the X^2 values were less than .05 (the critical value). The X^2 (Chi-Square) value testing the linked gene hypothesis equaled 135.33 and 115.75 was the ending sum testing the not linked hypothesis. These numbers were used to determine p-values. According to the given chart, these numbers indicate reason to doubt the hypotheses because the observed data differed significantly from the expected. As such “implies” the difference cannot be due only to chance sampling variation. Had the statistic been greater than the critical value the null hypothesis would have not been rejected? Reasons for this outcome range from numerous potential errors. It is possible I did not count and or observe all the flies in the vials. Flies often “escape” despite best efforts to contain them. Thus I may have had flies presented with wild type long wings and the recessive mutant gene for sepia eye color. It is very likely they flew away. It is possible that I may have done my count too early. Some flies were still in their pupae stage and thus yet to eclose. If the count was done two days later maybe different ratios would have been observed supporting one of the null hypotheses. Other error could have been the results of poor cultivating on my part. One could assume that the cultivated “virgin” females may very well not been virgin. This issue is of course one of the harder ones to address simply because the current lab and staff hours, school schedules, work schedules, etc. do not permit myself or anyone else to monitor the flies twenty-four hours daily until the experiments conclusion. Counting the cultivated flies may have been interrupted by more urgent issues (such as a class, ride home, etc.) thus making one careless and not as observant as they would normally be. Flies could have “hid” themselves under shed exoskeleton, the media, etc. thus it is possible all the adult flies were not removed from the vials after each count. Thus offspring could have been reproducing with parent, this in turn not providing adequate phenotypic expression. Numerous events could have, and most likely did occur, that generated the data presented. But the data is the data. I can not change the events of the past hence my observations are all that I can work with. More experimentation is recommended to determine if the null hypotheses truly should be rejected.
Conclusion
According to the data obtained in this experiment the null hypothesis that, there is no significant difference between what we observed and what we expect if the genes are linked, is to be rejected.
References
Flagg, Raymond. 1988. Carolina Drosophila Manuel.
Morgan, Judith. Carter, M. Eloise Brown. Benjamin Cummings 2002. Investigating Biology: Fourth Edition.
http://media.nasaexplores.com/lessons/04-006/images/life-cycle.gif
Thompson, David. 2006. BIO 150L: Introduction to Biology 1 Laboratory Manual.